Enumerable.generate enumerates the initial value, even if it doesn't pass the condition selector.

[trxcllnt]

@mattpodwysocki

I've always understood Enumerable.generate() to approximate for-loop style control flow. Is this wrong? Whereas the for-loop prints nothing, the generate example prints an undefined value to the console.

var arr = ["a", "b", "c"];
for(var i = 3; i < arr.length; ++i) {
    console.log(arr[i]);
}
// prints nothing

var arr = ["a", "b", "c"];
Enumerable.generate(
    3,
    function(i) { return i < arr.length; },
    function(i) { return i + 1; },
    function(i) { return arr[i]; }
).forEach(console.log.bind(console));
// prints `undefined`